1
0
Files
blog.xinshi.fun/source/special/wp/vnctf-2024.md

206 lines
5.7 KiB
Markdown
Raw Normal View History

2025-04-17 15:28:08 +08:00
---
title: VNCTF 2024 Writeup by LilRan
date: 2024/02/18 12:00:00
updated: 2024/02/18 12:00:00
categories:
- CTF-Writeup
cover: ../../wp/vnctf-2024/cover.jpg
2025-10-01 10:58:30 +08:00
permalink: wp/vnctf-2024/
2025-04-17 15:28:08 +08:00
---
摸了个第三也顺便加了好多师傅的QQ。隔壁同时进行的SICTF比VNCTF卷多了在SICTF我还不如新生🤣
<!-- more -->
![](../../wp/vnctf-2024/1.png)
## Reverse
### TBXO
用eax和栈实现的控制流汇编层面动态调试起来不难找到主要逻辑在sub_9610F4处写出解密程序。
```c
#include <stdio.h>
int main() {
unsigned char cipher[] =
{
0x10, 0x30, 0x36, 0x31, 0x23, 0x86, 0x93, 0xAD, 0xC5, 0xD4,
0x92, 0x84, 0x66, 0xE3, 0x67, 0x75, 0x6B, 0x69, 0x86, 0xC7,
0x31, 0x2E, 0x09, 0xA0, 0x33, 0x57, 0x69, 0xDB, 0x93, 0xA8,
0x13, 0xDD, 0x3E, 0xA5, 0xD8, 0x88, 0x37, 0x54, 0x84, 0x7E};
for(int i=0; i<5; i++) {
unsigned int d = 0;
for (int i = 0; i < 32; i++)
d -= 0x61c88647;
unsigned int r = ((unsigned int*)cipher)[2*i+1];
unsigned int l = ((unsigned int*)cipher)[2*i];
for(int j=0; j<32; j++) {
r -= ((l + d) ^ ((l << 4) + 0x79645f65) ^ ((l >> 5) + 0x6b696c69) ^ 0x33);
l -= ((r + d) ^ ((r << 4) + 0x67626463) ^ ((r >> 5) + 0x696d616e) ^ 0x33);
d += 0x61c88647;
}
((unsigned int*)cipher)[2*i] = l;
((unsigned int*)cipher)[2*i+1] = r;
}
printf("%s\n", cipher);
return 0;
}
```
🚩 `VNCTF{Box_obfuscation_and_you_ar_socool}`
### baby_c2
流量中只关注192.168.218.1与192.168.218.129的TCP流量即可第84条记录有D盘的文件列表flag.txt为43字节第121条记录有flag.txt的加密数据长度43从流量包本身信息可以知道当天是2月7日。
ps1脚本解base64的部分可以去掉iex然后丢进powershell跑最后一层是写一个PE文件到`%temp%\169sdaf1c56a4s5da4.bin`
NOP掉40131F处的call和ret、创建函数即可反编译。在405178和405088处会传入文件名对文件进行加密然后再传输。
~~长度不变的加密方式猜一个异或猜一个RC4~~
![](../../wp/vnctf-2024/2.png)
但我没找到RC4的实现在哪里对405178和405088处逐字节异或日期207后只得到了无意义递减字节。等一个WP。
> 后记:
>
> 一方面是要异或217另一方面是我IDAPython脚本写错了get_db_byte写成byte_value了捂脸
>
> ```python
> def my_patch(frm, sz, byt):
> for i in range(frm, frm+sz):
> idc.patch_byte(i, idc.get_db_byte(i) ^ byt)
>
> my_patch(0x405088, 234, 217)
> my_patch(0x405178, 206, 217)
> ```
>
> 然后转换为未定义U转换为代码C创建函数P反编译F5
🚩 `vnctf{84976be3-9809-4a3b-9711-51621e388286}`
## Crypto
### SignAhead
套路题,哈希长度扩展攻击
直接用https://github.com/JoyChou93/md5-extension-attack md5pad.py修改成用pwntools自动交互Python2运行。
```python
import md5py
import hashlib
import struct
from pwn import *
def payload(length, str_append):
pad = ''
n0 = ((56 - (length + 1) % 64) % 64)
pad += '\x80'
pad += '\x00'*n0 + struct.pack('Q', length*8)
return pad + str_append
def hashmd5(str):
return hashlib.md5(str).hexdigest()
context.log_level = 'debug'
c = remote('manqiu.top', 21926)
for _ in range(100):
c.recvuntil('msg: ')
msg = c.recvline().strip()
c.recvuntil('sign: ')
hash_origin = c.recvline().strip()
str_append = "LilRan :)"
lenth = 96
m = md5py.md5()
str_payload = payload(lenth, str_append)
c.recvuntil('msg: ')
c.send(msg)
for i in str_payload:
c.send(hex(ord(i))[2:].zfill(2))
c.sendline()
c.recvuntil('sign: ')
c.sendline(m.extension_attack(hash_origin, str_append, lenth))
print c.recvall()
```
![](../../wp/vnctf-2024/3.png)
🚩 `VNCTF{append_key_instead_of_message#6603db4e}`
## Misc
### ez_msb
GNU Radio启动
原wav数据按位与11111001flag平铺到00000??0。在wav刚开始零点几秒还没有音乐直接把flag那条路逆过来走就行可以得到纯净的flag。后面有音乐的位置就是乱码了并且不懂各种数据类型是怎么转换的等一个WP。
![](../../wp/vnctf-2024/4.png)
![](../../wp/vnctf-2024/5.png)
🚩 `VNCTF{gnuradio_best_radio_3de8b}`
### LearnOpenGL
这个好好玩,做得很精致😆
透过墙上缺的一个洞可以看见白色的线条而背景图素材上没有所以flag图层在背景图和砖块之间。想办法把砖块隐藏。
翻文件夹多次尝试发现这样patch一下就行。
![](../../wp/vnctf-2024/6.png)
![](../../wp/vnctf-2024/7.png)
🚩 `VNCTF{T3xtur3_M45t3r_0r_r3v_g405h0u_8703d0ccfef0}`
### sqlshark
上次做盲注流量还是在~~上次~~我第一次参加CTF的时候那时我还手动写了一页A4纸好怀念啊。这次用b神的轮子了。
```python
from FlowAnalyzer import FlowAnalyzer
pth = FlowAnalyzer.get_json_data('Misc/sqlshark/sqlshark.pcap', 'http')
for count, dic in enumerate(FlowAnalyzer(pth).generate_http_dict_pairs()):
response_num, response_data = dic['response']
request = dic.get("request")
if not request:
continue
request_num, request_data = request
if b'success!' in response_data and b'leAst' not in request_data:
dat = int(request_data.decode().split(r'%29%29%29%29in%28')[1].split(r'%29%29%29')[0])
print(chr(dat), end='')
# admin_p@ssw0rd
```
🚩 `VNCTF{admin_p@ssw0rd}`
### 问卷调查
🚩 `VNCTF{wen_juan_diao_cha}`
## Web
### Checkin
出题人电脑的F12按键坏了你能帮他按一按吗
![](../../wp/vnctf-2024/8.png)
![](../../wp/vnctf-2024/9.png)
🚩 `VNCTF{W31c0m3_t0_VNCTF_2024_g@od_J0B!!!!}`